Answer:
-1/3 or 1/2.
Step-by-step explanation:
Second term = ar, the third = ar^2 and the fourth = ar^3.
So we have the equation:
ar + ar^2 = 6ar^3
r + r^2 = 6r^3
6r^3 - r^2 - r = 0
r(6r^2 - r - 1) = 0
(3r + 1 )(2r -1) = 0
r = -1/3, 1/2.
<h2>Um I think its 143 i think im just guessing</h2>
Answer:
y = -5/2x + 20/3
Step-by-step explanation:
<u>x-int of 3x + 6y = 8</u>
sub 0 for y
3x + 6(0) = 8
3x = 8
x = 8/3 or 2.667
<u>line perpendicular to 2x - 5y = 10</u>
put into y = mx + b form
2x - 5y - 10 = 0
5y = 2x - 10
y = 2/5 x - 2
<u>find negative reciprocal of the slope 2/5 x (for the perpendicular line)</u>
-5/2 x
<u>find the y-int (b)</u>
m = -5/2 x
must pass through (8/3,0)
y = mx + b
0 = -5/2(8/3) + b
0 = -40/6 + b
b = 20/3
therefor the equation of the line is y = -5/2x + 20/3
Answer:
Option B. $84 U is the answer.
Step-by-step explanation:
Petrus Framing's cost formula for its supplies cost is $1,840 per month plus $12 per frame.
Standard supplies cost for the month of March is =
= $9328
But the actual level of activity for the month of March = 631 frames
Therefore, supplies cost on actual frames =
= $9412
The variance is =
= $84 U (option B)
<h3>
Answer: Perpendicular</h3>
The slopes -2/3 and 3/2 multiply to -1, which is sufficient info that the lines are perpendicular. Perpendicular slopes always multiply to -1 assuming neither line is vertical nor horizontal.
Note how -2/3 is the negative reciprocal of 3/2, and vice versa.