Answer:
Brent’s club has more possible team combinations because there are more members to choose from
Step-by-step explanation:
Brents club can be created in C12 6 =12!/6!/6!=7*8*9*10*11*12/(2*3*4*5*6)=
=924 variants
Miguel's club can be created in C10 6=10!/6!/4!=7*8*9*10/(2*3*4)=210 variants
924>210 so Brent’s club has more possible team combinations because there are more members to choose from
Since the sample is greater than 10, we can approximate this binomial problem with a normal distribution.
First, calculate the z-score:
z = (x - μ) / σ = (37000 - 36000) / 7000 = 0.143
The probability P(x > 37000$) = 1 - P(<span>x < 37000$),
therefore we need to look up at a normal distribution table in order to find
P(z < 0.143) = 0.55567
And
</span>P(x > 37000$) = 1 - <span>0.55567 = 0.44433
Hence, there is a 44.4% probability that </span><span>the sample mean is greater than $37,000.</span>
Answer:
yeah think so? have u done it?
<span>
EXAMPLE: A common source of frame error is the use of a telephone directory as a sampling frame for a telephone survey. Many houses are not liste</span>
A right triangle ABC is formed when we join three points around a lake. Length of the side AC = 6 miles. Length of the side BC = 2 miles. We have to find Length of side AB.Using Pythagorean theorem for Right triangle ABC , Right angled at B→AB² + BC²= AC²→ AB² + 2²= 6²→ AB² = 36 - 4→ AB²= 32→ AB = √ 32→→AB = 5.66 (approx)Option (B) AB = 5.66 is Right choice.
