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slavikrds [6]
2 years ago
7

What is a typical age (the mean) for the people who were at Movie A?

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

It is 39

Because you have to count the little dots all the way till it is around the most age.

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Question 6 of 10 The triangles shown below may not be congruent. 1) 25° 55° 100° 100° 66° 25° O A. True O B. False​
Blizzard [7]

Answer:

True, they may not be congruent

Step-by-step explanation:

A figure cannot be determined as congruent from three angles alone. In order  for two shapes to be congruent, all corresponding parts must be congruent. This means all the sides and angles of the two shapes must be the same in order for the two shapes to be congruent. If we know all the angles are the same, the sides could still be different lengths, so this does not prove congruency.

5 0
3 years ago
The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0
3 years ago
What is the exponential expression 24^1/3
guapka [62]

Answer:

2.884499

Step-by-step explanation:

3 0
3 years ago
What are the y-intercepts to graph the equation -4x – 3y = 36?
Alex787 [66]

4x-3y =36

Move the constant to the left by adding its opposite to both sides

4x-3y-36=36-36

The sum of two opposites equals 0

Answer: 4x-3y-36=0

PLEASE MARK ME AS BRAINLIEST

3 0
3 years ago
What is the inverse operation of division?
Step2247 [10]

Answer:

multiplication

7 0
3 years ago
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