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3 years ago

12

Solve for x. plz help

2 answers:

LiRa [457]3 years ago

7 0

$x^2-2x+10=0\\\\ (x^2-2x+1)-1+10=0\\\\(x-1)^2+9=0\\\\ (x-1)^2=-9$

Answer D

Gwar [14]3 years ago

7 0

Hello :
x²- 2x+10 = 0
(x²-2x+1) -1 +10
(x-1)² +9 = 0
(x-1)² = -9 ... .(no real solution because : (x-1)² <span>≥ 0 )</span>

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Answer:

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Step-by-step explanation:

| x | = x

|- x | = x

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OR

Given f ( x ) = 6

f( x ) = 2 | x + 6 | - 4

6 = 2 | x + 6 | - 4

6 + 4 = 2 | x + 6| - 4 + 4 [ adding 4 to both sides ]

10 = 2 | x + 6 | + 0

5 = | x + 6 | [ dividing both sides by 2 ]

$- 5 =\ ( x+ 6) \ = 5\\\\$ $[ \ | x | = a\ => \ -a \ = x \ = a \ ]$

$- 5 - 6 = \ x + 6 - 6 \ = \ 5 - 6\\$ $[ \ subtracting \ by \ 6 \ ]$

$-11 = \ x \ = - 1$

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