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Oliga [24]
3 years ago
8

Pls help me with this ans should be well explained ​

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0

Let's observe

#1st column

  • 3+2+1+4=10

10th alphabet=J

#2nd

  • 5+9+4+6=24

24th alphabet=X

#3rd

  • 2+1+3+3=9

9 th Alpha bet=I

#4th

  • 8+4+9+5=26

26th Alphabet=Z

#5th

  • 7+3+1+2=13

13 th alphabet=M

Option B is correct

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PLEASE ANSWER ASAP! SHOW ALL WORK! WILL GIVE BRAINLIEST!
Iteru [2.4K]

1) x^2=x\cdot x, and x(x+3)=x^2+3x. Subtracting this from the numerator gives a remainder of

(x^2-13x-48)-(x^2+3x)=-16x-48

-16x=-16\cdot x, and -16(x+3)=-16x-48. Subtracting this from the previous remainder gives a new remainder of

(-16x-48)-(-16x-48)=0

This means that

\dfrac{x^2-13x-48}{x+3}=x-16

2) 3x^3=3x^2\cdot x, and 3x^2(x+2)=3x^3+6x^2. Subtracting this from the numerator gives a remainder of

(3x^3-x^2-7x+6)-(3x^3+6x^2)=-7x^2-7x+6

-7x^2=-7x\cdot x, and -7x(x+2)=-7x^2-14x. Subtracting this from the previous remainder gives a new remainder of

(-7x^2-7x+6)-(-7x^2-14x)=7x+6

7x=7\cdot x, and 7(x+2)=7x+14. Subtracting this from the previous remainder gives a new remainder of

(7x+6)-(7x+14)=-8

This means that

\dfrac{3x^3-x^2-7x+6}{x+2}=3x^2-7x+7-\dfrac8{x+2}

3) x+2 will be a factor of x^3+3x^2-10x-24 if dividing the latter by x+2 leaves a remainder of 0.

x^3=x^2\cdot x, and x^2(x+2)=x^3+2x^2. Subtracting this from the numerator gives a remainder of

(x^3+3x^2-10x-24)-(x^3+2x^2)=x^2-10x-24

x^2=x\cdot x, and x(x+2)=x^2+2x. Subtracting this from the previous remainder gives a new remainder of

(x^2-10x-24)-(x^2+2x)=-12x-24

-12x=-12\cdot x, and -12(x+2)=-12x-24. Subtracting this from the previous remainder gives a new remainder of

(-12x-24)-(-12x-24)=0

and since the remainder is 0, x+2 is indeed a factor of x^3+3x^2-10x-24.

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