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soldier1979 [14.2K]
2 years ago
9

Which one is greater 2/3 or 4/5

Mathematics
2 answers:
marshall27 [118]2 years ago
4 0

Answer:

\frac{4}{5} is greater.        

Step-by-step explanation:

To find : Which one is greater \frac{2}{3} or \frac{4}{5} ?

Solution :

First we make the denominators of the fraction same to identify the greater term easily.

Multiply and divide \frac{2}{3} by 5,

\frac{2}{3}\times \frac{5}{5}=\frac{10}{15}

Multiply and divide \frac{4}{5} by 3,

\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}

Now, Comparing the numerator 12 > 10

So, \frac{12}{15}>\frac{10}{15}

Which means \frac{4}{5}>\frac{2}{3}

Therefore, \frac{4}{5} is greater.

Reptile [31]2 years ago
3 0

2/3 because it’s out of 3, if you cut a pizza in 3 slices the slices are bigger and if u take 2 out of the three the remaining piece is bigger than the 4/5 because those 5 pieces will be cut smaller

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What is the greatest common factor of the polynomial below 12x^2-9x
wlad13 [49]

Answer:

the greatest common factor of this is 3

3 0
3 years ago
Please help me<br> thanks
attashe74 [19]

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6 0
1 year ago
What is -x/3 = 9. Solve for x
vlada-n [284]

Note: I just noticed that you only have one negative sign. If you mean to put -9, change the sign to positive. If not, leave the answer.

Note the equal sign. what you do to one side, you do to the other. Isolate the x. First, multiply 3 to both sides

-x/3(3) = 9(3)

-x = 9(3)

-x = 27

Next, to isolate the x, divide -1 from both sides

-x/-1 = 27/-1

x = 27/-1

x = -27

-27 is your answer for x.

hope this helps

3 0
3 years ago
Read 2 more answers
A Mexican restaurant sells quesadillas in two sizes: a "large" 10 inch-round quesadilla and a "small" 5 inch-
elena-14-01-66 [18.8K]

Answer:

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^2

where

r is the radius

step 1

Find the area of the 10 inch-round quesadilla

we have

D=10\ in

r=10/2=5\ in

substitute

A=\pi (5)^2

A=25\pi\ in^2

step 2

Find the area of the 5 inch-round quesadilla

we have

D=5\ in

r=5/2=2.5\ in

substitute

A=\pi (2.5)^2

A=6.25\pi\ in^2

step 3

Which is larger, half of the 10-inch quesadilla or the entire 5-inch quesadilla?

Compare

half of the 10-inch quesadilla is equal to ----> \frac{1}{2}(25\pi)=12.5\pi\ in^2

the entire 5-inch quesadilla ---->6.25\pi\ in^2

therefore

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

3 0
2 years ago
Can anykne solve for any of these? If yiu can put what letter you did.
Aneli [31]
A) y - 8= -2/3 (x + 3)
B) y + 1 = 4 (x - 5)
C) y - 8 = -3/7 (x - 4)
D) y - 7 = 2/3 (x - 5)
E) y + 5 = -5/3 (x + 3)
4 0
3 years ago
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