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soldier1979 [14.2K]
3 years ago
9

Which one is greater 2/3 or 4/5

Mathematics
2 answers:
marshall27 [118]3 years ago
4 0

Answer:

\frac{4}{5} is greater.        

Step-by-step explanation:

To find : Which one is greater \frac{2}{3} or \frac{4}{5} ?

Solution :

First we make the denominators of the fraction same to identify the greater term easily.

Multiply and divide \frac{2}{3} by 5,

\frac{2}{3}\times \frac{5}{5}=\frac{10}{15}

Multiply and divide \frac{4}{5} by 3,

\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}

Now, Comparing the numerator 12 > 10

So, \frac{12}{15}>\frac{10}{15}

Which means \frac{4}{5}>\frac{2}{3}

Therefore, \frac{4}{5} is greater.

Reptile [31]3 years ago
3 0

2/3 because it’s out of 3, if you cut a pizza in 3 slices the slices are bigger and if u take 2 out of the three the remaining piece is bigger than the 4/5 because those 5 pieces will be cut smaller

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Share 800 in the ratio 9:7.
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<u>Answer:</u>

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<u>Step-by-step explanation:</u>

<u>Step-1: Add the ratios:</u>

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<u>Step-2: Divide 800 by the sum of the ratios:</u>

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<u>Step-3: Multiply 50 with each ratio:</u>

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An analysis of sales records for the last 120 weeks gives the following results. Assuming that these past data are a reliable gu
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Answer:

(a) 0.5333

(b) 0.6583

(c) 0.5583

(d) 0.7083

(e) 0.6167

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = a competitor will advertise

<em>NA </em>= a competitor will not advertise

<em>L </em>= Low sales will be achieved

<em>M </em>= Medium sales will be achieved

<em>H </em>= High sales will be achieved

The data provided is of the form:

          Low (L)    Medium (M)    High (H)    Total    

A            32                   14                 18               64

NA          21                   12                 23              56

Total      53                  26                 41              120

The probability of an event <em>E</em> is:

P(E)=\frac{n(E)}{N}

n (E) = favorable outcomes of event <em>E</em>

N = Total number of outcomes

(a)

Compute the probability that next week the competitor will advertise as follows:

P(A)=\frac{n(A)}{N}=\frac{64}{120}=0.5333

Thus, the probability that next week the competitor will advertise is 0.5333.

(b)

Compute the probability that next week sales will not be high as follows:

P(H^{c})=1-P(H)=1-\frac{n(H)}{N}=1-\frac{41}{120}=\frac{120-41}{120}=0.6583

Thus, the probability that next week sales will not be high is 0.6583.

(c)

The events of achieving a medium or high sales are mutually exclusive.

Since the sales achieved will either be medium or high. They cannot be both.

So, P (M ∩ H) = 0.

Compute the probability that next week there will be medium or high sales will be achieved as follows:

P(M\cup H)=P(M)+P(H)=\frac{26}{120}+\frac{41}{120}=\frac{26+41}{120}=0.5583

Thus, the probability that next week there will be medium or high sales will be achieved is 0.5583.

(d)

Compute the probability that next week either the competitor will advertise, or only low sales will be achieved as follows:

P(A\cup L)=P(A)+P(L)-P(A\cap L)=\frac{64}{120}+\frac{53}{120}-\frac{32}{120}=\frac{85}{120}=0.7083

Thus, the  the probability that next week either the competitor will advertise, or only low sales will be achieved is 0.7083.

(e)

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P(NA\cup H)=P(NA)+P(H)-P(NA\cap H)=\frac{56}{120}+\frac{41}{120}-\frac{23}{120}=\frac{74}{120}=0.6167

Thus, the  the probability that next week either the competitor will not advertise, or high sales will be achieved is 0.6167.

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