9514 1404 393
Answer:
4 1/2 days
Step-by-step explanation:
The time is given by ...
time = quantity/rate
time = (3/4 fence)/(1/6 fence/day) = (3/4)(6) days = 4 1/2 days
If it is perpendicular then the slope of it will be:
y = 1/3 x + b
-1 = (1/3)(3) + b
-1 = 1 + b
b = -2
The equation is:
You’ve got the correct answer (which is the first one) hope this helps
Answer:
Step-by-step explanation:
Let the rate at which the bacteria grow be represented by the exponential equation
P(t) = P0e^kt
P(t) is the population of the bacteria after time t
P0 is the initial population
k is the constant of variation
t is the time
If the initial Population is 160 bacteria's, them the equation becomes;
P(t) = 160e^kt
b) if After 5 hours there will be 800 bacteria, this means
at t = 5 p(t) = 800
Substitute and get k
800 = 160e^5k
800/160 = e^5k
5 = e^5k
Apply ln to both sides
Ln5 = lne^5k
ln5 = 5k
k = ln5/5
k = 0.3219
Next is to calculate the population after 7hrs i.e at t = 7
P(7) = 160e^0.3219(7)
P(7) = 160e^2.2532
P(7) = 160(9.5181)
P(7) = 1522.9
Hence the population after 7houra will be approximately 1523populations
c) To calculate the time it will take the population to reach 2790
When p(t) = 2790, t = ?
2790 = 160e^0.3219t
2790/160 = e^0.3219t
17.4375 = e^0.3219t
ln17.4375 = lne^0.3219t
2.8587 = 0.3219t
t = 2.8587/0.3219
t = 8.88 hrs
Hence it will take approximately 9hrs for the population to reach 2790
Answer:
<h2>: 7-⁴</h2>
Step-by-step explanation:
<h3>Exponential Form :</h3><h3>(a^m*a^n ) = (a^m+n )</h3>
<h3>7^-6 = 7^-2 * x </h3>
<h3>(only 7^-4 the term that can add to 7^-2 gives </h3><h3>= 7^-6 )</h3>
<h3>7^-6 = 7^-2 + 7^-4 </h3>
<h3> ( a^m*a^n) = ( a^m+n)</h3>
