Question

The first steps in writing f(x) = 3x2 – 24x 10 in vertex form are shown. f(x) = 3(x2 – 8x) 10 (startfraction negative 8 over 2 endfraction) squared = 16 what is the function written in vertex form? f(x) = 3(x 4)2 – 6 f(x) = 3(x 4)2 – 38 f(x) = 3(x – 4)2 – 6 f(x) = 3(x – 4)2 – 38

Answer 1

Answer:

The answer is D!

Step-by-step explanation:

Answer 2

The given quadratic equation 3x^2 – 24x + 10 can be written in vertex form that is f(x) = 3(x – 4)2 – 38.

What are quadratic equations?

A quadratic equation is an equation of degree 2 and the standard form of a quadratic equation $ax^{2} +bx+c$ where x is the variable and a,b, c are real numbers.

Following the steps already shown to transform the given function into the vertex form,

$f(x) = 3(x^{2} - 8x + 16) + 10 - 3(16)\\f(x) = 3(x - 4)(x - 4) + 10 - 48\\f(x) = 3(x - 4)2 - 38$

Therefore, the function written in vertex form is f(x) = 3(x – 4)2 – 38.

Learn more about quadratic equations;

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