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AlladinOne [14]
1 year ago
8

The angle of elevation to a nearby tree from a point on the ground is measured to be 66^{\circ} ∘ . How tall is the tree if the

point on the ground is 68 feet from the tree? Round your answer to the nearest tenth of a foot if necessary.
Mathematics
1 answer:
Nimfa-mama [501]1 year ago
6 0

By comparing with a right triangle, we will see that the height of the tree is 62.12ft

<h3>How tall is the tree?</h3>

We can compare the situation with a right triangle. Such that the hypotenuse measures 68 ft, and an angle measures 66°.

We want to get the height of the tree, which would be the opposite cathetus, then we can use the relation:

Sin(a) = (opposite cathetus)/hypotenuse.

Sin(66°) = H/68ft

Tan(66°)*68ft = H = 62.12ft

The height of the tree is 62.12ft

If you want to learn more about right triangles, you can read:

brainly.com/question/2217700

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=solve%20for%20%22m%22%20t%3D%5Cfrac%7Bms%7D%7Bm%2Bn%7D" id="TexFormula1" title="solve for &quo
dalvyx [7]

Answer:

\boxed{\sf \ \ \ m = -\dfrac{tn}{t-s} \ \ \ }

Step-by-step explanation:

Hello,

let s assume that m+n is different from 0

we have this equation and we need to find m as a function of t, s, and n

t=\dfrac{ms}{m+n}

<=>

(m+n)*t=ms\\\\ tm+tn=sm\\ (t-s)m = -tn\\ m = -\dfrac{tn}{t-s}

for t-s different from 0, so t different from s

hope this helps

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