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3 years ago

6

There are four red ,four blue, and two green marbles in a bag .if one marble is chosen at random from the bag what is the probab

ility that the marble will be green

1 answer:

mina [271]3 years ago

7 0

Answer:

There is a 20% probablity that the marble will be green :)

Step-by-step explanation:

There are a total of 10 marbles in the bag. 4 red+4 blue+ 2green=10
There are two green marbles out of the 10 marbles. 2/10
2 divided by 10 is .20 or 20%
Therefore, there is a 20% probability that the marble will be green.

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3 years ago

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Step-by-step explanation:

Mean volume = u = 1000

Standard deviation = $\sigma$ = 6

We need to find the proportion of bottles with volume greater than 994. So our test value is 994. i.e.

x = 994

Since the data is normally distributed we will use the concept of z-score to find the required proportion. First we convert 994 to its equivalent z-score, then using the z-table we will find the corresponding value of proportion. The formula to calculate the z score is:

$z=\frac{x-u}{\sigma}$

Substituting the values, we get:

$z=\frac{994-1000}{6}=-1$

This means 994 is equivalent to a z score of -1. Now we will find the proportion of z values which are greater than -1 from the z table.

i.e. P(z > -1)

From the z-table this value comes out to be:

P(z >- 1) = 1 - P(z < -1) = 1 - 0.1587 = 0.8413

Since, 994 is equivalent to a z score of -1, we can write that proportion of values which will be greater than 994 would be:

P( X > 994 ) = P( z > -1 ) = 0.8413 = 84.13%

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