Answer:
Step-by-step explanation:
100 + 100÷100 - 100 = 100 + 1 -100 {apply BODMAS}
= 101 - 100 = 1
1.59, 1.95, 9.15, 9.5, 15.9
Square root is not defined to for negative values. For negative values, the answer of square root is a complex number which is not in Real Domain.
So any such values, for which the expression is not defined are not in the Domian. So the domian of square root of x will be All real numbers greater than or equal to 0.
This can be expressed as:
[0 , ∞)
or
x ≥ 0
Answer:
At price 3 and 11, the profit will be $0
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
<em>
A certain companies main source of income is a mobile app. The companies annual profit (in millions of dollars) as a function of the app’s price (in dollars) is modeled by P(x)=-2(x-3)(x-11) which app prices will result in $0 annual profit?</em>
My answer:
Given:
- x is the app price
- P(x) is the profit earned
If we want to find out the app price that will result in $0 annual profit? It means we need to set the function:
P(x)=-2(x-3)(x-11) = 0
<=> (x-3)(x-11)= 0
<=> x - 3 = 0 or x - 11=0
<=> x = 3 or x = 11
So at price 3 and 11, the profit will be $0
Hope it will find you well.
Remember
a^2-b^2=(a-b)(a+b)
a.
ok so look at last bit
-9x^2+1
can be rearanged into
1-9x^2
look familiar?
1^2-(3x)^2
(1-3x)(1+3x) or
(1-3x)(3x+1)
we nowhave
(3x+1)(5x-4)-(x-12)(3x+1)+(1-3x)(3x+1)
factor out (3x+1)
(3x+1)(5x-4-(x-12)+1-3x)
(3x+1)(2x-3-x+12)
(3x+1)(x+9)
b.
easy
a^2-b^2=(a-b)(a+b)
(4x+5)^2-(2x-3)^2=
(4x+5-(2x-3))(4x+5+2x-3)=
(4x+5-2x+3)(6x+2)=
(2x+8)(6x+2)
we can factor out the 2 from each
(4)(x+2)(3x+1)
a(x)=(3x+1)(x+9)
b(x)=(4)(x+2)(3x+1)
