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malfutka [58]
3 years ago
14

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?
Mathematics
1 answer:
jasenka [17]3 years ago
3 0
Add all flowers to get denominator

4+3+4=11

now add carnations and roses

3+4=7

so your answer is

7/11 chance
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Leila and joe are two partners in a business. Leila makes $8 in profit for every $9 that joe makes. if joe makes $54 profit on t
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