Answer:
The probability that the 2nd Heads occurred at the 4th toss is 5.99%.
Step-by-step explanation:
Given that there were 4 Heads in the first 7 tosses, to find the probability that the 2nd Heads occurred at the 4th toss the following calculation must be performed:
7 - 4 = 3
4/7 x 3/7 x 3/7 x 4/7 = X
0.571 x 0.428 x 0.428 x 0.571 = X
0.0599 = X
Therefore, the probability that the 2nd Heads occurred at the 4th toss is 5.99%.
(x²+x)(x²+5x+6) = x^4 + 6x³ + 11x² + 6x + 1 ≥0
f(x) = x^4 + 6x³ + 11x² + 6x + 1
f'(x) = 4x³ + 18x² +22x +6
racines x1 = -0,301 x2 = -1,5 x3 = -2,618
variations
x -2,62 -1,5 -0,3
f'(x) - 0 + 0 - 0 +
f(x) -inf \ 0 / \ 0 /
on voit que cette fonction st toujours positive
Answer:
80
Step-by-step explanation:
80 is the main score I think.....
Given the equation 4(3b + 2)² = 64,
dividing both sides of the equation by 4, we have
(3b + 2)² = 16 and getting the square root of both sides,
(3b + 2) = 4 and (3b + 2) = -4
We can solve for b for each equation and have
3b = 2 | 3b = -6
b = 2/3 | b = -2
Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>
