Look at the picture.
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
Answer:
6
Step-by-step explanation:
Answer:
19%
Step-by-step explanation:
Answer:
(4+8)(4) = (x) 3
Step-by-step explanation:
The picture shows two secants intersecting at a point outside the circle. A beautiful pattern for this is: along each secant, the product (multiply) the <em>entire</em> secant by the <em>outside</em> part is the same.
(entire secant)(outside part) = (entire secant)(ouside part)
(4+8)(4) = (x)(3)