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Viefleur [7K]
2 years ago
15

Patrick added 1/4 teaspoons of cayenne pepper and 1/3 teaspoons of black

Mathematics
1 answer:
GalinKa [24]2 years ago
5 0
Find the lowest common denominator and add.
1/4 or 3/12 of cayenne + 1/3 or 4/12 of black pepper = 7/12 teaspoons of spices total
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There’s a full 12 piece pizza. Ayla got a slice of pizza and John got 1 and two half’s of pizza.....how many slices are left.
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Answer:

9

Step-by-step explanation:


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Suppose a random variable, x, arises from a binomial experiment. If n = 25, and p = 0.85, find the variance. Round answer to 4 d
Tamiku [17]

Answer:

<u><em>a) P(X=1) = 0.302526</em></u>

<u><em>b) P(X=5) = 0.010206</em></u>

<u><em>c) P(X=3) = 0.18522</em></u>

<u><em>d) P(X≤3) = 0.92953</em></u>

<u><em>e) P(X≥5) = 0.010935</em></u>

<u><em>f) P(X≤4) = 0.989065</em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>If helpful, please mark as brainliest! =)</em></u>

8 0
3 years ago
Please helpppp!?!!!!?
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It would be 9!!!
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3 0
2 years ago
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There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
Marcus daims that in the expression 3x + 3y, the terms 3x and 3y are like terms because both are variable terms and both have th
kumpel [21]

Answer:

Step-by-step explanation:

3x and 3y are not "like terms," despite having the same coefficient.

Like terms have the same variable. For example, 3x and 2x are like terms, so

3x+2x = 5x

7 0
2 years ago
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