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3 years ago

9

Plz help me with it

2 answers:

Gekata [30.6K]3 years ago

8 0

Answer: a. 1

<u>Step-by-step explanation:</u>

$\sqrt{2x+7}+1=\sqrt{2x+14}\\\\(\sqrt{2x+7}+1)^2=(\sqrt{2x+14})^2\\\\2x+7+2\sqrt{2x+7}+1=2x+14\\\\2x+8+2\sqrt{2x+7}=2x+14\\\\2\sqrt{2x+7}=6\\\\\sqrt{2x+7}=3\\\\(\sqrt{2x+7})^2=(3)^2\\\\2x+7=9\\\\2x=2\\\\x=1\\\\\\Check:\\\sqrt{2(1)+7}+1=\sqrt{2(1)+14}\\\\\sqrt9+1=\sqrt16\\\\3+1=4\ \checkmark$

vovangra [49]3 years ago

5 0

$\sqrt{2x + 7} + 1 = \sqrt{2x + 14 } \\ x = 1$

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