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marin [14]
3 years ago
9

Plz help me with it

Mathematics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:  a. 1

<u>Step-by-step explanation:</u>

\sqrt{2x+7}+1=\sqrt{2x+14}\\\\(\sqrt{2x+7}+1)^2=(\sqrt{2x+14})^2\\\\2x+7+2\sqrt{2x+7}+1=2x+14\\\\2x+8+2\sqrt{2x+7}=2x+14\\\\2\sqrt{2x+7}=6\\\\\sqrt{2x+7}=3\\\\(\sqrt{2x+7})^2=(3)^2\\\\2x+7=9\\\\2x=2\\\\x=1\\\\\\Check:\\\sqrt{2(1)+7}+1=\sqrt{2(1)+14}\\\\\sqrt9+1=\sqrt16\\\\3+1=4\ \checkmark

vovangra [49]3 years ago
5 0

\sqrt{2x + 7}  + 1 =  \sqrt{2x + 14 }  \\ x = 1
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