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kumpel [21]
2 years ago
14

You volunteer to help drive children at a charity event to the zoo, but you can fit only 6 of the 15 children present in your va

n How many different groups of 6 children can you drive?​
Mathematics
1 answer:
shtirl [24]2 years ago
6 0

<u><em>However if you are asking how many different combinations, there can be 5005 different combinations.</em></u>

Answer:

<u><em>2 different groups of 6 children.</em></u>

Step-by-step explanation:

<u><em>There are 15 children </em></u><u><em>you need to bring. </em></u><u><em>You can fit 6 children in each van.</em></u>

<u><em>One van : 6 children</em></u>

<u><em>Two vans : 12 children</em></u>

<u><em>Three vans : 18 children</em></u>

<u><em>If you take </em></u><u><em>two vans, that will take 12 children</em></u><u><em>. But you need to fit 15.</em></u>

<u><em>If you take </em></u><u><em>three vans, that will take 18 children.</em></u><u><em> This is more than enough.</em></u>

<u><em>15 children - 6 = 9 children</em></u>

<u><em>Thats one group with 9 children left to take</em></u>

<u><em>9 children - 6 = 3 children</em></u>

<u><em>Thats two groups with 3 children left to take</em></u>

<u><em>3 children - 6 = -3.</em></u>

<u><em>This doesn't work. In this case, </em></u><u><em>there will be 3 more empty seats in the last group.</em></u>

<u><em>Since the question asks how many groups of </em></u><u><em>6 </em></u><u><em>children you can drive. It would be </em></u><u><em>two. </em></u><u><em>Becuase </em></u><u><em>there are 2 groups of 6 and one of 3</em></u><u><em>.</em></u>

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Step-by-step explanation:

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3 years ago
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ankoles [38]

For this case we must follow the following rules of rounding

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Therefore, the steps for rounding to the nearest tenth is:

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2) Therefore, the next number stays the same

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3 years ago
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USPshnik [31]

Answer:

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Step-by-step explanation:

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max2010maxim [7]

Answer:

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Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

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By substitutition:

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Using an double-angle identity:

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Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

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Answer: x= -2

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