<h3>
Answer: B) Only the first equation is an identity</h3>
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I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
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Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.
Answer:
11 Students
Step-by-step explanation:
It is hard to explain in my opinion but I can try. For the stem column you, basically factor out the first digit of the number. Then the leaf column you, put the second digit of each number in your data set.
Answer:
2nd answer : 6
Step-by-step explanation:
144-36=108
6
Answer:
The area of the rectangle is 1222 units²
Step-by-step explanation:
The formula of the perimeter of a rectangle is P = 2(L + W), where L is its length and W is its width
The formula of the area of a rectangle is A = L × W
∵ The length of a rectangle is 5 less than twice the width
- Assume that the width of the rectangle is x units and multiply
x by 2 and subtract 5 from the product to find its length
∴ W = x
∴ L = 2x - 5
- Use the formula of the perimeter above to find its perimeter
∵ P = 2(2x - 5 + x)
∴ P = 2(3x - 5)
- Multiply the bracket by 2
∴ P = 6x - 10
∵ The perimeter of the rectangle is 146 units
∴ P = 146
- Equate the two expression of P
∴ 6x - 10 = 146
- Add 10 to both sides
∴ 6x = 156
- Divide both sides by 6
∴ x = 26
Substitute the value of x in W and L expressions
∴ W = 26 units
∴ L = 2(26) - 5 = 52 - 5
∴ L = 47 units
Now use the formula of the area to find the area of the rectangle
∵ A = 47 × 26
∴ A = 1222 units²
∴ The area of the rectangle is 1222 units²
