Find the terms and the coefficients of the expression.

1 answer:

3 0

The terms are -80, 4p, and -6z.
The coefficients are 4 and 6.

Terms are separated by the addition and subtraction sign.
Coefficients are the numbers that go in front of the variable.

You might be interested in

What 946 x 1367 = what

dlinn [17]

The answer to your question is 1,293,182

7 0

3 years ago

Read 2 more answers

Suppose taxi fare from Logan Airport to downtown Boston is known to be normally distributed with a standard deviation of $2.50.

Mariulka [41]

Answer:

95% Confidence interval for taxi fare: ($20.5,$24.2)

Step-by-step explanation:

We are given the following data set: for fares:

$22.10, $23.25, $21.35, $24.50, $21.90, $20.75, and $22.65

Formula:

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{156.5}{7} = 22.35$

95% Confidence interval:

$\bar{x} \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$22.35 \pm 1.96(\frac{2.5}{\sqrt{7}} ) = 22.35 \pm 1.85 = (20.5,24.2)$

6 0

2 years ago

sally gave her brother 3.95 in quarters and dimes. if the number of quarters is 6 more then the number of dimes, how many quarte

iragen [17]

Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)

(2)-> q-d= 6
q-d+d= 6+d
q= 6+d...(2a)

(2a)-> (1) 0.25q+0.10d=3.95
0.25(6+d)=0.10d= 3.95
1.95+0.25d+0.10d= 3.95
0.35d= 3.95-1.5
0.35d/0.35= 2.45/0.35
d= 7...(3)

(3)->(2) q-d= 6
q-7= 6
q=6+7
q= 13
There are 13 quarters and 7 dimes.

7 0

2 years ago

PLEASE ANSWER QUICKLY! THANK YOU :) <br><br>

Natalka [10]

It’s not b or d so it’s either a or c. Hope this helped

4 0

3 years ago

3y-4=6- 2y<br> y=?<br> solve pleaseeeeeeeeeee

dybincka [34]

Y= 2 is the answer
Hope this helps

4 0

2 years ago

Read 2 more answers