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True [87]
2 years ago
15

Solve for n: -1/2 (n + 8) +3/4

Mathematics
1 answer:
vlabodo [156]2 years ago
7 0

\frac{1}{2} (n+8) + \frac{3}{4}

\frac{1(n+8)}{2}  +  \frac{3}{4}

\frac{n+8}{2}  +  \frac{3}{4}

\frac{2(n+8)}{4}  + \frac{3}{4}

\frac{2(n+8) + 3}{4}

\frac{2n + 16 +3}{4}

\frac{2n + 19}{4}

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Given that a = -1, b=2 and c= -3 ,find the value of a(b2+c2)
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Answer:

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Step-by-step explanation:

Given that a = -1, b=2 and c= -3

find the value of a(b^{2}+c^{2})

Just substitute the values given for each variable

a(b^{2}+c^{2}) = (-1)(2^{2}+(-3)^{2}) ; do the exponents first

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a(b^{2}+c^{2}) = -13 ; and multiply by -1

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