Answer:
A
Step-by-step explanation:
Answer:
SAS
And I don’t know if your going to give me a cookie. We need to social distance you know ;)
<span>What is the y-intercept of the plane whose equation is 4x + 5y + z = 20?
(0, 4, 0)
Which equation has intercepts at X(1, 0, 0), Y(0, 1, 0), and Z(0, 0, 2)?
2x + 2y + z = 2
Which equation is equivalent to x + 3y + z = 3?
4x + 12y + 4z = 12
Which of the following points lies in the plane 3x + 2y + 4z = 12?
(4, 3,2)
Hope these answer the questions. Have a nice day.</span>
Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!