Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
Answer:
5 Minutes
take 10 and add 12 for each minute until you pass 60
D is correct because you could put in a value for x and get a true value for y
exg
x=3
y=14(3)-9
y=42-9
y=33
Answer:
it will take him 16 weeks
Step-by-step explanation:
290 subtract 50 equals 240
240 divided by 15 equals 16
