Answer:
1.71
Step-by-step explanation:
by using definition of cos

Answer:
Median is 31, if you are talking about the parallel line in between JK and and ML
Answer:
w^3 × 1/w^9
I'm pretty sure that's the answer
X^2(x)+5x(x)+6/x(x)+1(x)=1(x)
X^3+5x^2+6+x=x
X^3+5x^2+6=0
Use cube
X is approx -5.220181
The slope of the function is given by its derivative. You want to find the values of x such that the derivative is between -1 and 1.
... f'(x) = 0.4x +5
... -1 < 0.4x +5 < 1 . . . . . your requirement for slope
... -6 < 0.4x < -4 . . . . . . subtract 5
... -15 < x < -10 . . . . . . . multiply by 2.5
Any value of x that is between -15 and -10 will be one where the tangent line has a slope between -1 and 1.
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The graph shows tangent lines with slopes of -1 and +1. You can see that the slope of the graph of f(x) is between those values when x is between the tangent points.