Let's solve ~
[ according to given figure ]
Correct choice is D
5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
90
Step-by-step explanation:
THAT WAS OBVIOUS
Answer: 11
Step-by-step explanation:
It is 11 because count from -6...
-6 = 0
-5 = 1
-4 = 2
-3 = 3
-2 = 4
-1 = 5
0 = 6
1 = 7
2 = 8
3 = 9
4 = 10
5 = 11
Hope this helpsand sorry if not
She would place it before the 4.
