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2 years ago

10

The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as

he moves the herd. The arc the handler makes from the starting point to the return point should be a quarter of a circle:
A sector showing a quarter of a circle is drawn. The radius is marked as 75 feet. The endpoints of the arc of the sector are marked as Starting Point and Return Point. The sector is filled with cattle.

Based on this theory, what distance will the handler move from the starting point to the return point if he creates an arc of a circle with radius 75 feet?
1884 feet
4415.63 feet
58.88 feet
117.75 feet

1 answer:

Reika [66]2 years ago

6 0

Answer:

117.75 feet

Explanation:

This the answer that I got and it's correct. I hope this helps.

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Answer: gravity affect only the mass

Step-by-step explanation:

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2 years ago

Kevin using 84 fluid ounces of water to make in all purpose cleaner. The directions call for 4 fluid ounces of concentrated soap

nata0808 [166]

He should use 886 fluid ounces of soap.

<u>Step-by-step explanation</u>:

Know that 8 fluid ounces make 1 cup.

Now 24 cups need 32 fluid ounces or, 3 fluid ounces of water need 32 fluid ounces of soap.

Thus, by unitary method,

84 ounces of water need 32 × 84 / 3 ounces of soap.

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2 years ago

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

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$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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The figure below shows a shaded region and a non-shaded region. Angles in the figure that appear to be right angles are right an

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Answer:

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Step-by-step explanation:

The red shaded lines had numbers as well so I add all of them up.

The non-shaded lines didn't have a number, but the bottom had the same length of the top line so therefore your answer is 26 for Shaded, and 16 for non-shaded.

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2 years ago

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