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andre [41]
2 years ago
6

Can somebody please help me I will mark u brilliant

Mathematics
1 answer:
givi [52]2 years ago
3 0

Answer:

2/7 + (-3/4) + (-2/7) + 4/3

If we look at 2/7 and (-2/7), we can see that both of them combined will get you a result of 0, so let's do that first.

2/7 + (-2/7) = 0

Now we're left with;

(-3/4) + 4/3

Make sure to convert both fractions into having a common denominator,

[They both have a common denominator of 12], so:

(-3/4) = (-9/<u>12</u>)

4/3 = 16/<u>12</u>

Add them:

(-9/12) + 16/12

16/12 - 9/12

= <u>7/12</u>, which cannot further be simplified.

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\bf 3x+4y=9\implies 4y=-3x+9\implies y=-\cfrac{3x+9}{4}\implies y=\stackrel{slope}{-\cfrac{3}{4}}x+\cfrac{9}{4} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{4}{3}}\qquad \stackrel{negative~reciprocal}{+\cfrac{4}{3}}\implies \cfrac{4}{3}}


so we're really looking for the equation of a line whose slope is 4/3 and runs through 8, -4.


\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{-4})~\hspace{10em} slope =  m\implies \cfrac{4}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{4}{3}(x-8) \implies y+4=\cfrac{4}{3}x-\cfrac{32}{3} \\\\\\ y=\cfrac{4}{3}x-\cfrac{32}{3}-4\implies y=\cfrac{4}{3}x-\cfrac{44}{3}

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