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2 years ago

Can somebody please help me I will mark u brilliant

Mathematics

1 answer:

givi [52]2 years ago

3 0

Answer:

2/7 + (-3/4) + (-2/7) + 4/3

If we look at 2/7 and (-2/7), we can see that both of them combined will get you a result of 0, so let's do that first.

2/7 + (-2/7) = 0

Now we're left with;

(-3/4) + 4/3

Make sure to convert both fractions into having a common denominator,

[They both have a common denominator of 12], so:

(-3/4) = (-9/<u>12</u>)

4/3 = 16/<u>12</u>

Add them:

(-9/12) + 16/12

16/12 - 9/12

= <u>7/12</u>, which cannot further be simplified.

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What is one of the solutions to the following system of equations? y2 x2 = 53 y − x = 5 (−10, −5) (−7, −2) (7, 2) (5, 10).

Aliun [14]

The solution of the system of equation is (-7, -2).

<h2>Given</h2>

The system of the equations;

$\rm y^2 + x^2 = 53 \\\\y -x = 5$

From equation 1

$\rm y -x=5\\\\y = 5+x$

Substitute the value of y in equation 1

$\rm y^2+x^2=53\\\\(5+x)^2+x^2=53\\\\25+x^2+10x+x^2=53\\\\2x^2+10x+25-53=0\\\\2 x^2 + 10x - 28 = 0 \\\\Divide \ by \ 2 \ both \ side \ the \ equation\\\\x^2 + 5x - 14 = 0\\\\x^2-7x+2x-14=0\\\\x(x-7) + 2(x-7) =0\\\\(x-7) \ (x+2)=0\\\\x-7=0 \ \ x = 7\\\\x +2 =0 \ \ x=-2$

The value of x= 2 is rejected because x = 2 not satisfy the equation.

Substitute 2 for the value of x in equation II

y − x = 5

y – 2 = 5

y = 5 +2

y = 7 (x =2, y =7) … Not included in the options

If x = -7

Substitute the value of x = -7 in the equation

$\rm y -x=5\\\\y - (-7)=5\\\\y +7= 5\\\\y = 5-7\\\\y = -2$

Hence, the solution of the system of equation is (-7, -2).

To know more about System of Equation click the link given below.

brainly.com/question/1495351

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2 years ago

What is 2x+y=1 in slop intercept form?

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3 years ago

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Which expression is equivalent to the expression below?(6c^2+3c/-4c+2)/(2c+1/4c-2)

algol [13]

Answer:

-3c

Step-by-step explanation:

The given expression is:

$\frac{\frac{6c^{2}+3c}{-4c+2}}{\frac{2c+1}{4c-2}}$

We need to simplify this expression. The rational expression in the denominator can be multiplied to numerator by taking its reciprocal as shown below:

$\frac{\frac{6c^{2}+3c}{-4c+2}}{\frac{2c+1}{4c-2}} \\\\ =\frac{6c^{2}+3c}{-4c+2} \times \frac{4c-2}{2c+1}\\\\=\frac{3c(2c+1)}{-(4c-2)} \times \frac{4c-2}{2c+1}\\\\ =-3c$