Solution :
Mean time for an automobile to run a 5000 mile check and service = 1.4 hours
Standard deviation = 0.7 hours
Maximum average service time = 1.6 hours for one automobile
The z - score for 1.6 hours = 
= 2.02
Now checking a normal curve table the percentage of z score over 2.02 is 0.0217
Therefore the overtime that will have to be worked on only 0.217 or 2.017% of all days.
Answer:
y = -3/2x + 6
Step-by-step explanation:
We won't be able to figure out Y in number form, since we have a second variable, but we can figure it out in terms of X.
First, we have to subtract 6x from both sides
( -4y = -6x + 24 )
Then we have to divide both sides by -4
( y = -3/2x + 6 )
This is our final answer in terms of x
Graph using the end point and a few selected points.
x|y
0|0
1|2
2|2.83
8 / x^2. 8 is the y variable, and any number squared equals the x variable
