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marysya [2.9K]
3 years ago
9

A large cube has 5 layers, each with 5 rows of 5 small cubes. How many small cubes will the larger cube contain? Explain Please

Mathematics
2 answers:
kolbaska11 [484]3 years ago
7 0
You would do 5*5*5 and that equals 125
Flura [38]3 years ago
5 0
125 because 5 times 5 times 5 equals 125
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Mark walked 1212 miles in 5 hours. How many miles did Mark walk in 1 hour?
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Step-by-step explanation:

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Write the rule for this pattern:2,4,7,14,17,34
Masja [62]

Answer:

The rule is x₁ = 2   x₂ = x₁ * 2    x₃ = x₂ + 3    x₄ = x₃ * 2    x₅ = x₄ + 3 ...

Step-by-step explanation:

Unable to use a single equation to define this sequence

The rule is x₁ = 2   x₂ = x₁ * 2    x₃ = x₂ + 3    x₄ = x₃ * 2    x₅ = x₄ + 3 ...

Multiply 2 then Plus 3 then multiply 2 then plus 3 ......

2,4,7,14,17,34, 37, 74, 77, 154....

6 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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