Jo.

Mathematics

1 answer:

AleksAgata [21]2 years ago

3 0

Oh okie so sorry sorry about the delay in

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Constructed Response

Len [333]

Answer:

Check Explanation.

Step-by-step explanation:

Totally, Terrell has 4 protein/meat options and 3 sauce options to pick from.

Meat Options: beef, pork, chicken, or tofu.

Sauce Options: hot, tangy and sweet sauce.

Individually, he could just pick each of the options, but now, the sample space would involve a combination of a protein option and a sauce option. So, the total sample spaces available would be every choice of protein and sauce available.

Using the fundamental counting principle,

A choice of beef meat will be followed by choice of either hot, tangy and sweet sauce giving a sample space of

(beef, hot), (beef, tangy), (beef, sweet)

This can then be repeated across the meat choices

(pork, hot), (pork, tangy), (pork, sweet)

(chicken, hot), (chicken, tangy), (chicken, sweet)

(tofu, hot), (tofu, tangy), (tofu, sweet)

Bringing the total sample spaces to

(beef, hot), (beef, tangy), (beef, sweet), (pork, hot), (pork, tangy), (pork, sweet), (chicken, hot), (chicken, tangy), (chicken, sweet), (tofu, hot), (tofu, tangy) and (tofu, sweet)

Making a total of 12 sample spaces!

Hope this Helps!!!

6 0

3 years ago

The sculpture consists of five identical prisms. JD says the surface area of the sculpture is 44 times the surface area of one p

larisa86 [58]

The complete question in the attached figure

we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy

now
JD says the surface area of the sculpture is 4 times the surface area of one prism
[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy

we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is greater in comparison with the real value
This is because JD should also subtract the areas of eight hidden surfaces.

the answer is
JD should also subtract the areas of eight hidden surfaces