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Keith_Richards [23]
2 years ago
9

If you are going 10.5 mph how long would it take to go 6,776 miles?​

Mathematics
2 answers:
loris [4]2 years ago
8 0

Answer: 10.5 mph

Step-by-step explanation:

faust18 [17]2 years ago
6 0

Answer: 21.

Step-by-step explanation:

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Danielle spent 35$ on a magazine and some notepads. If the magazine cost 3$ and each notepad cost 4$ then how many notepads did
kifflom [539]
She bought 8 notepads
3 0
3 years ago
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what is the equation to seven less than the product of twice a number is greater than 5 more than the same number
postnew [5]
<span>seven less than (-7) than the product of twice a number (2x) is greater than (>) five more than (+5) the same number (x)

2x-7>x+5
treat the > sign as an equals for now
2x-7=x+5
subtract x from both sides
x-7=5
add 7 to both sides
x=12
put the > sign back in
x>12</span>
7 0
3 years ago
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A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
(10x5)+(30+20)x10-100-1=
Flauer [41]

Answer:

899 would be your answer

Step-by-step explanation:

10x5=50

50+30=80

80+20=100

100x10=1000

1000-100=900

900-1=899

Hope this helps you!

5 0
3 years ago
Read 2 more answers
A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price
Nataliya [291]

Answer:

a) P=3(120-s)+200

b) 215 \leq P \leq 290

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

s number of seats, if w analyze the info given the number of seats after increase the price is given by 120-s.

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

P-200=3(120-s)

So then our linear equation is given by:

P=3(120-s)+200

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

P_L=3(120-90)+200=290

P_U=3(120-115)+200=215

So the corresponding range of ticket prices is:

215 \leq P \leq 290

4 0
3 years ago
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