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1 year ago

Solve the follwing please:

Mathematics

1 answer:

myrzilka [38]1 year ago

3 0

$\dfrac{(-9-11)/(-4)}{-7^2+(11 \times 2^2)}\\\\=\dfrac{(-20)/(-4)}{-49+44}\\\\=\dfrac{5}{-5}\\\\=-1$

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ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

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Answer:

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Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

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Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

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Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

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Thus we could see that the sides EF = FG

So it is a isosceles triangle.

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Answer:

Step-by-step explanation:

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