Y = x + 2
Djdhskfbtbekdbfbekskfnrbs
just subsitute
f(4)=4²+3(4)-1
f(4)=16+12-1
f(4)=28-1
f(4)=27
it approaches 27 as x approaches 4
<h2>Answer:
The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ). </h2>
<h3 /><h3>Step-by-step explanation:
</h3>
<u>Find the slope of the parallel line</u>
When two lines are parallel, they have the same slope.
⇒ if the slope of this line = - 8
then the slope of the parallel line (m) = - 8
<u>Determine the equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - 11 = - 8 (x - (-1))
∴ y - 11 = - 8 (x + 1)
We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:
since y - 11 = - 8 (x + 1)
y = - 8 x + 3
The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ).
Answer:
when u multiple it it us 100 but when I added it was 21
so it is 100 or 21 sorry if it is not right
Answer:
y=3/2x+1
Step-by-step explanation:
y-4= -⅔(x-6)
y-4=-⅔x+4
y=-⅔x+4+4
(equation of line 1) y= -⅔x+8 gradient= -⅔
(line 2)gradient=3/2
note* the gradients of perpendicular lines multiplied result to -1
gradient=<u>y²-y²</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹
<u>3</u><u> </u>=<u>y</u><u>+</u><u>2</u>
<u> </u><u> </u>2. x+2
multiply both sides by 2(x+2)to remove the denominators
3(x+2)=2(y+2)
3x+6=2y+4
3x+6-4=2y
3x+2=2y
divide all sides by 2
3/2x+1=y
y=3/2x+1
