Solve the following "marginal-revenue function" problem below

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

4 0

Answer:

$65,139,000

Step-by-step explanation:

Integration of the given function involves straightforward application of the power rule. It can also be done easily by a modern calculator.

$\displaystyle \int_{1000}^{1300}{(190x-1370)}\,dx=95(1300^2-1000^2)-1370(1300-1000)\\\\=95(300)(2300)-1370(300)=300(95\cdot2300-1370)\\\\=65\,139\,000$

Revenue from the sale of those 300 tickets will be $65,139,000.

You might be interested in

What is the simplified form of the complex fraction? 2x2+7x+6x2+x−64x2−9x2−5x+6

kiruha [24]

Answer:

3x - 124

Step-by-step explanation:

kindly find solutions in the picture above

6 0

3 years ago

If the mean of a normally distributed population is -10 with a standard deviation of 2, what is the likelihood of obtaining a va

ira [324]

Answer:

93.32% probability of obtaining a value less than or equal to -7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = -10, \sigma = 2$