The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>
From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation
This gives
Evaluate the products
Evaluate the like terms
So, we have
f(x) = x²+ 2/3x - 1/9
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(x + 3) (x + 2) = 0
To solve it, the most appropriate technique is:
1.) zero product property
The solutions are:
(x + 3) = 0
x = -3
(x + 2) = 0
x = -2
x² + 6 = 31
To solve it, the most appropriate technique is:
2.) square root property
x² = 31-6
x² = 25
x = +/- root (25)
x = +/- 5
The solutions are:
x = 5
x = -5
