Which of the following points are in the second quadrant of the xy plane?
2 answers:
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Answer:
Step-by-step explanation:
First, find the slope of the line for the two points.
Slope is Rise/Run.
For the two points (-8,-4) and (3,-10):
Rise (-10 - (-4)) = -6
Run (3 - ( -8)) = 11
The slope is Rise/Run or -(6/11)
The equation becomes y = -(6/11)x + b
Find b by entering either of the 2 points given. I'll use (3,-10):
y = -(6/11)x + b
-10 = -(6/11)(3) + b
b = -10 + (6/11)(3)
b = -10 +(18/11)
b = -(110/11) + (18/11)
b = -(92/11)
The equation becomes y = -(6/11)x - (92/11)
See attached graph.
