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eduard
4 years ago
10

“21 less than three-fifths of a number”

Mathematics
1 answer:
Amanda [17]4 years ago
4 0
3/5x-21 is the answer(I think) if not it’s 21-3/5x
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1/2+(-5/8) please help me I really need help have a great day
daser333 [38]

Answer:

-0.125

Step-by-step explanation:

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3 years ago
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the square of a certain whole number n is n^2. if 60 is a factor of n^2, it's possible that ? is not a factor of n^2. a)16 b)25
DanielleElmas [232]
If 60 is a factor of n², then √60 is a factor of n. However, n is a whole number, so its factors are whole numbers.

Simplify √60:
\sqrt{60}=\sqrt{4 \times 15}=2\sqrt{15}

If 2√15 is a factor of a whole number n, then √15 must be another factor to make it a whole number.

2\sqrt{15} \times \sqrt{15}=2 \times 15=2 \times 3 \times 5

If 60 is a factor of n², then 2, 3, and 5 must be factors of n. The factors of n² are the squares of the factors of n, so 2, 2, 3, 3, 5, and 5 must be factors of n².

Now, if 2, 2, 3, 3, 5, and 5 are factors of n², then:
* 5×5=25 must also be its factor
* 2×2×3×3=36 must also be its factor
* 2×2×5×5=100 must also be its factor

Only 16 may not be a factor of n². The answer is A.
4 0
3 years ago
Please help me thanks​
Brrunno [24]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
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What is Value for N=3.5
lutik1710 [3]

welll you know the valu now¿

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP
laila [671]
<h3><u>Option A</u></h3>

4 x^{2}+32 x-80=0 is the required equation to calculate width of rectangular frame that has a total area of 140 square inches.

<h3><u>Solution:</u></h3>

Given that,

Length of a rectangular frame is given as 2x + 10

Width of the rectangular frame is given as 2x + 6

Total area = 140 square inches

<em><u>The area of rectangular frame is given as:</u></em>

\text {area of rectangle}=\text {length } \times \text {width}

Plugging in values, we get

\begin{array}{l}{(2 x+10)(2 x+6)=140} \\\\ {4 x^{2}+12 x+20 x=80} \\\\ {4 x^{2}+32 x-80=0}\end{array}

This is the required equation to calculate width of rectangular frame

Solve the above quadratic equation to get the value of "x"

4 x^{2}+32 x-80=0

<em><u>Use the quadratic equation formula:</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here a = 4 ; b = 32 ; c = -80

x=\frac{-32 \pm \sqrt{32^{2}-4(4)(-80)}}{2(4)}

x=\frac{-32 \pm \sqrt{2304}}{8}

x = 2 or x = -10

Now measurement cannot be negative, so taking the positve value of "x", we can calculate the width

So put "x" = 2

Width of the rectangular frame = 2x + 6 = 2(2) + 6 = 10

Thus the width of frame is 10 inches

4 0
3 years ago
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