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Answer:
In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6
Step-by-step explanation:
Answer:
∠LPN = 57°
Step-by-step explanation:
arc LMN = 360° - 102° - 144° = 114°
∠LPN = 114°/2 = 57°
If you change the fraction to decimals that will make it easier to compare
(1/2) / 5 = 1/2 * 1/5 = 1/10 of a lb
