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2 years ago

Evaluate the following division: (3b-6a)÷(30a-15b)

Mathematics

1 answer:

shutvik [7]2 years ago

7 0

Evaluate the following division: (3b-6a)÷(30a-15b) is <u>-</u><u>1</u><u>/</u><u>5</u><u>.</u>

<h2><u>INTRODUCTION</u></h2>

~ Algebraic Forms and their Elements

Algebraic form is a mathematical form whose presentation involves symbols or letters to represent unknown numbers.

Elements of Algebra:

1. Variables, Constants and Coefficients

Pay attention to the algebraic form 3x + 2y + 3

From the algebraic form above, x and y are variables (variables), while the number 3 is a constant. A variable is a substitute symbol for a number whose value is not clearly known. While constants are terms of an algebraic form in the form of numbers and do not contain variables.

And what is meant by the coefficient is the constant factor of a term in algebraic form. The coefficient on the 3x term is 3, on the 2y term it is 2.

2. Terms and Factors

» The term is part of the algebraic form which is limited by the operation of addition (+) or difference (-). The term one is an algebraic form that is not connected by the operation of addition or difference.

Example: 2x, 2a², -4xy, . . .

» Term two is an algebraic form that is connected by an operation of sum or difference.

Example: 2x + 3, a² - 4, 3x² - 4x, . . .

» Similar terms in algebraic form are terms that have the same variable and the same power.

Example:

2a is similar to 3a, 4a, etc.

» Factors are part of the algebraic form that is restricted to multiplication operations.

Example: 5n = 5 × n, 5 and n are factors of 4n, respectively.

Calculation Operations on Algebraic Forms

1. Addition and subtraction of algebraic forms can only be done on similar terms.

2. Multiplication and division of algebraic forms.

Multiply two terms by constants or variables.

Example:

3 (4y + 5)

= (3 × 4y) + (3 × 5)

= 12y + 15

Division of two terms with a variable or constant, for example:

(8y+4)/2 = 8y/2 + 4/2 = 4y + 2

<h2><u>DISCUSSION</u></h2>

(3b-6a)÷(30a-15b)

= (-6a + 3b) ÷ (-5(-6a+3b))

= (-6a+3b)/(-5(-6a+3b))

= -1/5

<h3>Conclusion:</h3>

So, Evaluate the following division: (3b-6a)÷(30a-15b) is -1/5.

<h3>Learn More:</h3>

(mampir ke indo:v)

Algebraic subtraction material: https://brainly.co.id/task/35216852
Algebraic arithmetic operations: https://brainly.co.id/task/26250852
The equation of the value of x in algebraic form: https://brainly.co.id/task/42124780

_____________

<h3>Answer Details:</h3>

Class: 7 Middle School

Subject: Math

Material: Chapter 2.1 -Operations of Algebraic Forms

Categorization Code: 7.2.2.1

Keywords: Simple form of algebra

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Answer:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

$\bar X =237$ represent the sample mean

$\sigma = 47$ represent the population deviation

$n =30$ represent the sample size selected

$\mu_0 = 247$ represent the value that we want to test.

The standard error for this case is given by:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

For the 90% confidence the value of the significance is given by $\alpha=1-0.9 = 0.1$ and $\alpha/2 = 0.05$ so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

$z_{\alpha/2}= 1.64$

And the margin of error would be:

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

The confidence interval for this case would be given by:

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

Replacing into formula (b) we got:

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

P-value

Since is a left tailed test the p value would be:

$p_v =P(z$

Conclusion

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Evaluate the following division: (3b-6a)÷(30a-15b)​

Evaluate the following division: (3b-6a)÷(30a-15b)