1. 4(n+3)=16, n+3=4, n=1
2. m/4+3=24, m/4=21, m=84
1. three added to a number n implies n+3, 4 times that sum is 4 (n+3), to solve divide both sides by 4 then subtract three from both sides.
2. a number divided by 4 means n/4 adding it to three n/4+3, to solve subtract 3 from both sides then multiply both sides by 4
11.424242
isolate the repeating part
11+0.424242
focus on the repeating part
0.42424242
how many places till it repeats again?
2
let's say it is x
x=0.42424242
multiply by 100
100x=42.424242
subtract them
100x-x=42.42424242-0.42424242
the infinite repeats cancel and we get
99x=42
divide by 99

so