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3 years ago

Please give me the correct answer

Mathematics

1 answer:

katovenus [111]3 years ago

7 0

Answer:

Area= 452.23 ft²

Step-by-step explanation:

Angle at U = 180-48-20

Angle at U = 112°

UT/sin 112=46/sin 48

UT= 0.9272*46/0.7431

UT=57.4 ft

UV= sin 20*46/sin48

UV= 0.3420*46/0.7431

UV= 21.2 ft

S=( 21.2+57.4+46)/2

S=124.6/2

S= 62.3

Area= √((62.3)(62.3-21.2)(62.3-57.4)(62.3-46))

Area= √((62.3)(41.1)(4.9)(16.3))

Area= √204509.5311

Area= 452.23 ft²

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Please help me please will give brainliest show all your work thank you

Alika [10]

Answer:

Perimeter: 52 Area: 181-16i?

Step-by-step explanation:

Perimeter

The formula for perimeter is 2l+2w, so you plug in the binomials they give you:

2(11-4i)+2(15+4i)

expand:

22-8i+30+8i

combine like terms (which cancels out 8i and -8i):

22+30=52

Area

"i" is not a real number and thus should not be part of the area here, meaning this answer as it is is wrong and I don't know how one would change that.

Here's what I did to get 181-16i, in any case:

The formula for area is l*w, so I plugged in the numbers:

(11-4i)(15+4i)

expanded:

165+44i-60i-16i*i

and combined like terms:

181-16i

*i is $\sqrt{-1}$ , so $i^{2}$ =-1 and -1*-16=16.

5 0

3 years ago

JUANITA WANTS TO PARTICIPATE IN A 20 KILOMETER BICYCLE RACE. SHE IS CONSIDERING TWO TRAINING PROGRAMS BELOW. PROGRAM A: RIDE 10

barxatty [35]

She would ride 17,343.75 kilometers in three days because the first day is 7,500 meters and the get the third day you multiply that by .75 which would be 5,625, and to get the third day you would multiply the 5,625 by .75 to get about 4,218. Lastly, you would add the three numbers together

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3 years ago

A rectangular park measuring 32 yards by 24 yards is surrounded by a trail of uniform width. If the area of the park and the tra

cluponka [151]

Answer:

The width = 38 yard

Step-by-step explanation:

Given

Dimension of Park = 32 by 24 yard

Area = 1748 yd²

Required

Find the width of the park

Given that the park is surrounded by a trail;

Let the distance between the park and the trail be represented with y;

Such that, the dimension of the park becomes (32 + y + y) by (24 + y + y) because it is surrounded on all sides

Area of rectangle is calculated as thus;

Area = Length * Width

Substitute 1748 for area; 32 + 2y and 24 + 2y for length and width

The formula becomes

$1748 = (32 + 2y) * (24 +2y)$

Open Bracket

$1748 = 32(24 + 2y) + 2y(24 + 2y)$

$1748 = 768 + 64y + 48y + 4y^2$

$1748 = 768 + 112y + 4y^2$

Subtract 1748 from both sides

$1748 -1748 = 768 -1748 + 112y + 4y^2$

$0 = 768 -1748 + 112y + 4y^2$

$0 = -980 + 112y + 4y^2$

Rearrange

$4y^2 + 112y -980 = 0$

Divide through by 4

$y^2 + 28y - 245 = 0$

Expand

$y^2 + 35y -7y - 245 = 0$

Factorize

$y(y+35) - 7(y + 35) = 0$

$(y-7)(y+35) = 0$

Split the above into two

$y - 7 = 0\ or\ y + 35 = 0$

$y = 7\ or\ y = -35$

But y can't be less than 0;

$So,\ y = 7$

Recall that the dimension of the park is 32 + 2y by 24 + 2y

So, the dimension becomes 32 + 2*7 by 24 + 2*7

Dimension = 32 + 14 yard by 24 + 14 yard

Dimension = 46 yard by 38 yard

Hence, the width = 38 yard

5 0

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Elena-2011 [213]

Answer:

-5 coach tickets

-8 first class tickets

Step-by-step explanation:

let x be the number of coach tickets and y the number of first class tickets:

$x+y=13\ \ \ \ \ \ ...i$

Given that coach tickets costs $260 each, and first class tickets $1080 and that the total fare budget was $9940:

$260x+1080y=9940\ \ \ \ \ \ \ \ \ ...ii$

#From equation i, make x the subject of the formula:

$x=13-y$

#Substitute x in ii;

$260x+1080y=9940\\\\260(13-y)+1080y=9940\\\\3380-260y+1080y=9940\\\\820y=6560\\\\y=8\\\\x=13-y\\\\\therefore x=13-8=5$

Hence, Sarah bought 5 coach tickets and 8 first class tickets.

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