Answer:
you can't logically do this, even if you spend the entire time babysitting, you will not have enough for the 300
Step-by-step explanation:
Sorry this isn't an answer
Answer:
The signal would have experienced aliasing.
Step-by-step explanation:
Given that:
the bandwidth of the signal
= 36MHz
= 36 × 10⁶ Hz
The sampling frequency
= 36 × 10⁶ Hz
Suppose the sampling frequency is equivalent to the bandwidth of the signal, then aliasing will occur.
Therefore, according to the Nyquist criteria;
Nyquist criteria posit that if the sampling frequency is more above twice the maximum frequency to be sampled, a repeating waveform can be accurately reconstructed.
∴
By Nyquist criteria, for perfect reconstruction of an original signal, i.e. the received signal without aliasing effect;
Then,

∴
The signal would have experienced aliasing.
Answer:
1. y=5 and x=-5
2. y=2 and x=-4
Step-by-step explanation:
1.y=-5x-19
y=-6x-24
since both equations are equal to y, they are also equal to eachother
-5x-19=-6x-24
addition P.O.E.
x-19=-24
addition P.O.E.
x=-5
substitute x into one equation
y=-5*-5-19
y=6
2. y=-6x-22
y=-3x-10
since both equations are equal to y, they are also equal to eachother
-6x-22=-3x-10
addition P.O.E.
-22=3x-10
addition P.O.E.
-12=3x
division P.O.E.
-4=x
substitute x into one equation
y=-3*-4-10
y=2
Answer:
t = 3c
Step-by-step explanation:
Answer:
John received 10% of the overall votes.
Step-by-step explanation:
Let us assume that the number of votes John got = m
So, the number of votes Vivienne received = 3 times (John's share )
= 3 times m = 3 m
Also, The number of Votes Nassim received = 2 times ( Vivienne's share)
2 x (3 m) = 6 m
Total Votes in the grade 6
= Votes received by { John + Vivienne + Nassim}
= m + (3 m) + (6 m) = 10 m
Hence, the total number of students who voted in grade 6 = 10 m

= 
or, The percentage of John's Votes = 10%
Hence, John received 10% of the overall votes.