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2 years ago

Which scenario most likely describes an example of plagiarism?

Mathematics

1 answer:

valina [46]2 years ago

6 0

Answer: Taking a Photo of another photo displayed in an art gallery and claiming it as your own

Step-by-step explanation: Because you are claiming something as your own(when it's not) is considered plagiarism and no other situation is considered plagiarism but this one so really the process of elimination explains the answer to this question

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How does a digit in the ten thousands place compare to a digit in the thousands place?

andre [41]

Um I think it's like because there's a zero difference like ten thousands have more zeros

3 0

2 years ago

Explain how you could use a number line to determine -5 -(-3) What is the difference?

AURORKA [14]

Answer:

The difference is -2

7 0

3 years ago

PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION

Alex17521 [72]

Solution:

$\sqrt{4x + 13} = x + 2$

First square both sides.

$= > ( \sqrt{4x + 13} ) ^{2} = (x + 2) ^{2}$

Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

$= > 4x + 13 = {(x)}^{2} + 2 \times x \times 2 + (2) ^{2} \\ = > 4x + 13 = {x}^{2} + 4x + 4$

Now, transpose 4x and 4 to LHS.

$= > 4x - 4x + 13 - 4 = {x}^{2} \\$

Now, do the addition and subtraction.

$= > {x}^{2} = 9 \\ = > x = \sqrt{9} \\ = > x = ±3$

Answer:

x = ± 3

Hope you could understand.

If you have any query, feel free to ask.

3 0

2 years ago

Am i correct? calculus

Advocard [28]

Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer. That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

$\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\
$

$\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}$

8 0

3 years ago

You need new shoes for work which cost $70. You earn $400 net income each week, but have expenses totaling $380 each week. If yo

Nadya [2.5K]

Answer:

4 weeks

Step-by-step explanation:

Remaining money (per week) :

Net income - Expenses
$400 - $380
$20

No. of weeks to buy shoes :

Cost of shoes / Remaining money (per week)
$70/$20
3.5 ≈ 4 weeks (nearest whole week)

5 0

2 years ago