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Volgvan
3 years ago
10

Could I get some help on these please? Will give points.

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

X=-4, Y=22, idk about the CBD

Step-by-step explanation:

4y+2=90 degrees

subtract 2 on both sides you would get

4y=88 divide 4 with 88 and get 22

solve both X's so 5x+6=3x-2

i would subtract 3x first so i can get

2x+6=-2

then subtract 6 on both sides so you would have

2x=-8 divide -8 with 2 and get -4  

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Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

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The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

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Therefore, the required polynomial is x^2+x-12.

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