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lyudmila [28]
3 years ago
14

Need some help asap​

Mathematics
1 answer:
Semenov [28]3 years ago
3 0
Sure! What’s the question (sorry if you provided an image I appear to not be able to see it)
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KengaRu [80]

Answ

Step-by-step explanation:

7 0
3 years ago
Which transformations have been applied to the graph of f(x) = x2 to produce the graph of g(x) = –5x2 + 100x – 450? Select three
RSB [31]

Answer:

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

Step-by-step explanation:

we have

f(x)=x^{2}

This is a vertical parabola open upward

The vertex is a minimum

The vertex is the origin (0,0)

g(x)=-5x^{2}+100x-450

This is a vertical parabola open downward

The vertex is a maximum

The first thing to note is that fx) is a parabola that opens up and g(x) opens down, so a reflection across the x-axis must have been applied.

Find the vertex of g(x)

Convert to vertex form

g(x)=-5x^{2}+100x-450

Complete the square

g(x)=-5(x^{2}-20x)-450

g(x)=-5(x^{2}-20x+100)-450+500

g(x)=-5(x^{2}-20x+100)+50

g(x)=-5(x-10)^{2}+50

The vertex is the point (10,50)

so

To translate the vertex of (0,0) to (10,50)

The rule of the translation is

(x,y) ------> (x+10,y+50)

That means ----> The translation is 10 units at right and 50 units up

therefore

The transformations are

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

5 0
3 years ago
Read 2 more answers
64978256+8734965+709685+1<br><br> Who ever answers correctly first gets Brainliest!!!!
anyanavicka [17]

Answer:

64978256+8734965+709685+1 = 74,422,907

5 0
3 years ago
Sam sent an email ro 3 friends on Monday. Each of the friends then sent an email to 3 friends on Tuesday. On Wednesday, each of
ivann1987 [24]
3*3*3 here you go!! Hope this helps
7 0
3 years ago
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Using basic trigonometric identities simplify the
katrin2010 [14]

Answer:

b

Step-by-step explanation:

Using the trigonometric identities

cot x = \frac{cosx}{sinx} and tan x = \frac{sinx}{cosx} thus

\frac{cos0}{cot0} + tanΘ × cosΘ

= \frac{cos0}{\frac{cos0}{sin0} } + \frac{sin0}{cos0} × cosΘ

= cosΘ × \frac{sin0}{cos0} + sinΘ

= sinΘ + sinΘ

= 2sinΘ → b

6 0
3 years ago
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