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2 years ago

Blowing up a balloon and letting it go is an example of newton’s.

Physics

1 answer:

Sladkaya [172]2 years ago

7 0

Answer:

Third Law Of Motion

Explanation:

When we let go of the end, the air rushes out and pushes against the air around the balloon to move it in the opposite direction. Newton describes this effect in his third law.

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A typical wall outlet voltage is 120 volts in the United States. Personal MP3 players require much smaller voltages, typically 2

butalik [34]

Answer:

Number of turns in secondary will be 7

Explanation:

We have given primary voltage $V_p=120volt$

Number of turns in the primary is $N_p=3575$

Secondary voltage is given $V_s=235mV=0.235volt$

We have to find the number of turns in secondary

We know that $\frac{N_p}{N_s}=\frac{V_p}{V_s}$

So $\frac{3575}{N_s}=\frac{120}{0.235}$

$N_s=6.60$

As the number of turns can not be in decimal so number of turns will be 7

6 0

4 years ago

How many Joules in 41.87 kcal?

gladu [14]

The answer is 175184.08 joules

4 0

3 years ago

Read 2 more answers

A 10-kilogram mass is sliding along a frictionless floor with an acceleration of 5 meters per second squared. What is the magnit

mart [117]

Answer:

<h3>The answer is 50 N</h3>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question we have

force = 10 × 5

We have the final answer as

Hope this helps you

5 0

3 years ago

A car is traveling in uniform circular motion on a section of flat roadway whose radius is . The road is slippery, and the car i

Alona [7]

Answer:

The smallest radius will be four (4) times the initial radius

Explanation:

The car maintains a constant angular speed. According to Newton's Second Law F = m a

1. $F_{r}=m*A_{n}$

2. $A_{n}=\frac{v^2}{R_{p}}$

Replacing 2 in 1

3. $F_{r}=m*\frac{v^2}{R_{p}}$

Where:

Fr= Frictional force

Rp= Initial Radius

An= Centripetal Acceleration

M= Mass

V= Velocity

Also we have that:

4. $F_{r}=\mu *W=\mu*m*g$

μ= Coefficient of friction between the car and the surface

M= Mass

W= Weight

G= Gravity

r is cleared from equation 3

5. $R_{p}=m*\frac{v^2}{F_{r}}$

Replacing 4 in 5

6. $R_{p}=m*\frac{v^2}{\mu*m*g}$

Simplifying

7. $R_{p}=\frac{v^2}{\mu*g}$

Now we have a new velocity equal to twice the initial velocity, We replace it by 2v in equation 7

8. $R_{n}=\frac{(2v)^2}{\mu*g}$

Computing

9. $R_{n}=\frac{4v^2}{\mu*g}$

Replacing 5 in 9

$R_{n}=4*R_{p}$

8 0

3 years ago

PLEASE HELP WILL GIVE BRANIST IT WOULD REALLY BE APPRICATIED

Natasha_Volkova [10]

Answer:

solids are strong and compact, they are not compressable.

liquids are flexible and less compacts they can not be coompresed

4 0

3 years ago