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Whitepunk [10]
3 years ago
8

Technician A says that failure analysis will assist the technician in determining whether it is more cost effective to replace r

ather than repair an engine. Technician B says that when an engine fails under warranty, the manufacturer may want it back for complete analysis of why it failed. Who is correct?
Physics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

The correct option is;

Technician A

Explanation:

Here we note  failure analysis will assist in determining the cause of failure and as such to determine the cost effectiveness of a repair or a replacement.

However, a warranty is a legal contract between the buyer of the engine and the manufacturer for the manufacturer to either repair the engine or compensate the the customer for all failures that occur within the period of the warranty. Therefore, technician B is not correct as he says the manufacturer may request the engine for analysis on why it failed which is not the same as the basis of a warranty.

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4 years ago
A vector A makes an angle of 20 degree and B makes an angle of 110 degree with the x-axis. The magnitude of this vectors are 3 m
Fofino [41]

The resultant is 5 m at 73.1^{\circ}

Explanation:

To solve the problem, we have to resolve each of the two vectors into its component along the x-axis and the y-axis.

Vector A has magnitude 3 m and angle 20 degrees with the x-axis, so its components are

A_x = A cos \theta = (3)(cos 20)=2.82 m

A_y = A sin \theta = (3)(sin 20)=1.03 m

Vector B has magnitude 4 m and angle 110 degrees, so its components are

B_x = B cos \theta = (4)(cos 110)=-1.37 m

B_y = B sin \theta = (4)(sin 110)=3.76 m

So, the x- and y- components of the resultant vector are

R_x = A_x + B_x = 2.82+(-1.37)=1.45 m\\R_y = A_y+B_y = 1.03+3.76 =4.79 m

Therefore the magnitude of the resultant is

R=\sqrt{R_x^2+R_y^2}=\sqrt{(1.45)^2+(4.79)^2}=5.0 m

While the direction is given by

\theta=tan^{-1}(\frac{R_y}{R_x})=tan^{-1}(\frac{4.79}{1.45})=73.1^{\circ}

Learn more about resultant of two vectors:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

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