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RUDIKE [14]
3 years ago
6

A rocket moves upward from rest with an acceleration of 40 m/s2 for 5 seconds. It then runs out of fuel and continues to move up

ward. Neglecting any air resistance, how high will it rise?
Physics
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

Maximum height of rocket  = 2538.74 m

Explanation:

We have equation of motion s = ut + 0.5 at²

For first 5 seconds

          s = 0 x 5 + 0.5 x 40 x 5² = 500 m

Now let us find out time after 5 seconds rocket move upward.

We have the equation of motion v = u + at

After 5 seconds velocity of rocket

         v = 0 + 40 x 5 = 200 m/s

After 5 seconds the velocity reduces 9.8m/s per second due to gravity.

Time of flying after 5 seconds

          t=\frac{200}{9.81}=20.38s

Distance traveled in this 20.38 s

          s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m

Maximum height of rocket = 500 +2038.74 = 2538.74 m

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3 years ago
a rectangular coil of 25 loops is suspended in a field of 0.20wb/m2.the plane of coil is parallel to the direction of the field
statuscvo [17]

Answer:

The current in the coil is 60 Ampere.

Explanation:

Given:

Number of turns in the coil is N = 25

Dimension of the coil = 15cm X 12cm

magnitude of magnetic field = 0.20T

angle in the xy plane is θ = 0 degree

torque τ = 5.4 N-m

To find:

current in the coil is i = ?

Solution:

The torque acting on the coil is given by

=> \tau = NiAB cos\theta

Converting cm to m

12 cm = 0.12 m

15 cm = 0.15 m

The area of the coil is  

A = 0.12 X 0.15

A = 0.018 m^2

Substituting the values

=>5.4 = 25\times i \times 0.018 \times 0.20 \times cos\theta

=>5.4 = 25\times i \times 0.018 \times 0.20 \times cos(0)

=>5.4 = 25\times i \times 0.018 \times 0.20 \times 1

=>5.4 = 25\times i \times 0.018 \times 0.20 \times 1

=>5.4 = 0.09\times i

=>i = \frac{5.4}{0.09}

=> i = 60 A

3 0
4 years ago
While studying physics at the library late one night, you noticethe image of the desk lamp reflected from the varnished tabletop
Natalija [7]
<h2>Answer: 1.73</h2>

Explanation:

The situation described here is known as polarization by reflection. This was discovered by Scottish physicist David Brewster and then formulated the law that bears his name:

<em>"When a beam of light hits the surface that separates two non-conducting media characterized by different electromagnetic characteristics (electrical permittivity and magnetic permeability), part of it is reflected back to the source medium, and part is transmitted to the second medium."</em>

This polarization happens when the light incides at a specific angle, called the Brewster angle (\theta_{B}), which is given by the following formula (<u>taking into account that generally the magnetic permeabilities of the two media involved do not vary):</u>

tan\theta_{B}=\frac{n_{2}}{n_{1}}     (1)

Where n_{2} is the index of refraction of the second medium (the varnish in this case) and n_{1}=1 is the index of refraction of the first medium (the air).

Now, if we are told the angle between the incident and reflected rays is 120\°, this means the incident angle is the half (60\°), which is the Brewster angle in this case.

So, \theta_{B}=60\°   (2)

Rewriting (1) with this incident ray angle:

tan(60\°)=\frac{n_{2}}{1}   (3)

n_{2}=tan(60\°)  

Finally we obtain the index ofrefraction of the varnish:

n_{2}=1.732

5 0
4 years ago
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