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alexgriva [62]
3 years ago
15

A ddr4 dimm with a pc rating of pc4-17000 is running at what speed?

Computers and Technology
1 answer:
leonid [27]3 years ago
8 0
Here is the answer:

A DDR4 ram module with that kind of rating would be running at a speed of 2133 megahertz. The pc4-17000 basically means that the particular ddr4 module has a bandwidth of 17000 megabytes per second.

Hope my answer has come to your help.
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The first graph in the picture describes a relation that is (a) Reflexive, transitive, and anti-symmetric.

Because a, b, c, d all are related to itself, so reflexive.

where (a, b) and (b, d) are in the relation, (a,d) is in the relation,    

for (c,a) and (a,b) there is (c,b).

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for all a,b in the relation, (a,b) there is no (b,a) with a ≠b.

The second graph in the picture describes a relation that is (b) Reflexive, transitive, and neither symmetric nor anti-symmetric.

Because a, b, c, d all are related to itself, so reflexive.

where (a, b) and (b, a) are in the relation, (a,a) is in the relation,                                                    

where (c, d) and (d, d) are in the relation, (c,d) is in the relation,                                                    

so it's transitive.

Because, (a,b) and (b.a) are there, but for (c,d) there is no (d,c) in relation.

So, the relation is not symmetric.

(a,b) and (b,a) is in relation but, a≠b, so not anti symmetric.

Explanation:

For all a in a set,  if (a,a) in a relation then the relation is reflexive.

For all (a,b) in relation R, if (b,a) is also in R, then R is symmetric.

For all (a,b), (b,c) in relation R, if (a,c) is also in R, then R is transitive.

For all (a,b), (b,a) in R, a = b,  then R is an anti- symmetric relation.

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