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wel
2 years ago
15

B%207%29" id="TexFormula1" title=" \tt(6x4−2x3 +7x2 −x) + ( 7x4+ 2x3−5x + 7)" alt=" \tt(6x4−2x3 +7x2 −x) + ( 7x4+ 2x3−5x + 7)" align="absmiddle" class="latex-formula">
\\

With Solution!!​​
Mathematics
2 answers:
Arturiano [62]2 years ago
5 0

Answer:

13(x)⁴ + 7(x)²-6(x) + 7

Explanation:

\hookrightarrow \sf (6x^4 -2x^3+7x^2-x)+(7x^4+2x^3-5x+7)

<u>remove the parenthesis</u>

\sf \hookrightarrow 6x^4-2x^3+7x^2-x+7x^4+2x^3-5x+7

<u>group the variables</u>

\hookrightarrow \sf 6x^4+7x^4-2x^3+2x^3+7x^2-x-5x+7

<u>add similar terms</u>

<u />\sf  \hookrightarrow  13x^4+7x^2-x-5x+7

<u>simplify</u>

\hookrightarrow \sf 13x^4+7x^2-6x+7

Vadim26 [7]2 years ago
3 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \tt \dashrightarrow \:\tt(6x {}^{4} −2x {}^{3}  +7x {}^{2} −x) + ( 7x {}^{4} + 2x {}^{3} −5x + 7)

\qquad \tt \dashrightarrow \:\tt6x {}^{4} −2x {}^{3}  +7x {}^{2} −x +  7x {}^{4} + 2x {}^{3} −5x + 7

Now, move all like terms aside :

\qquad \tt \dashrightarrow \:6 {x}^{4}  + 7 {}x^{4}  - 2 {x}^{3}  + 2 {x}^{3}  + 7 {x}^{2}  - x - 5x + 7

Add the like terms ~

\qquad \tt \dashrightarrow \:13 {}x^{4}   + 7 {x}^{2}   + 6x + 7

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Y=8-2x when x=8 the value of y
Lera25 [3.4K]

Answer:

-8

Step-by-step explanation:

Given that x and y are two variables.  they are related by the function

y =8-2x

Since x and y are related, given one value we can find the other using this equation.

In our question, given that x =8

Substitute x value in the equation

y = 8-2x

y =8-2(8) = -8

Hence answer is -8:


Verify:  We verify by putting -8 for y and check whether x =8

-8=8-2x

Or 2x = 16

x =8

Verified

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3 years ago
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2 years ago
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Twice a number x exceed 5 at least by 4. find the possible value of x.
salantis [7]

Answer:

5?

Step-by-step explanation:

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Find element a23 if matrix A, if A=|2 -3 4|<br> |5 0 -6|<br> |7 2 -8|
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Find all integers $n$ for which $\frac{n^2+n+1}{n-1}$ is an integer.
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