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antiseptic1488 [7]
2 years ago
9

Cab u help me find the answer ​

Mathematics
2 answers:
brilliants [131]2 years ago
5 0

Answer:

-1.25

Step-by-step explanation:

a=15

b=-5

If you plug the values into the equation you get

-5^2/15+5

-25/20

If you simplify that you will get:

-4/5

Or:

-1.25

e-lub [12.9K]2 years ago
3 0

Answer:

6

Step-by-step explanation:

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Help please help me please​
madam [21]

Answer:

B

Step-by-step explanation:

Only 1 because

1/1 = 1

2/1 = 2

The answer can't be 0 because we can't divide by zero.

The answer can't be 2 because you can't divide 1 by 2 without having a number with decimal places

Same thing for the 4

6 0
2 years ago
Read 2 more answers
H/52 = 88/44 what does H=
loris [4]
I believe the answer is 104.
7 0
3 years ago
The Vice President Of Sales Took A Client Out To Lunch. If The Lunch Was $44 And She Gave A 20% Tip, How Much Money Did She Spen
Ray Of Light [21]
The answer is 52.80 because the tip is $8.80 and 44.00+8.80=52.80
3 0
3 years ago
Which expression is not a polynomial?
Nezavi [6.7K]

Answer:

D.

Step-by-step explanation:

A term in a polynomial is a single number or a number multiplied by any number of variables. A polynomial is a sum of terms.

The only thing that can be done with variables in a polynomial is to multiply them by numbers or other variables. In a polynomial, you cannot: divide by a variable (have a variable in a denominator), have a root of a variable, have a log of a variable, have a variable as an exponent, etc.

All expressions are polynomials except for D. In D., the negative exponents mean division by variables.

7 0
2 years ago
According to a Washington Post-ABC News poll, 331 of 502 randomly selected U.S. adults interviewed said they would not be bother
k0ka [10]

Answer:

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

p_v =P(z>7.124)=5.24x10^{-13}  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is significantly higher than 0.5.  

Step-by-step explanation:

Data given and notation

n=502 represent the random sample taken

X=331 represent the adults that said they would not be bothered if the NAtional security agency

\hat p=\frac{331}{502}=0.659 estimated proportion of people who would not be bothered if the NAtional security agency

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than the majority of 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>7.124)=5.24x10^{-13}  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is significantly higher than 0.5.  

4 0
3 years ago
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