Find the circumcenter of the triangle with vertices at A(2,4), B(8, 4), and C(6, 10).
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Solution: If we are allowed to use only lower case letters, then we have 26 letters available with us. From these 26 letters the number of different arrangements of 6 letters is:
Now if we are allowed to use only upper case letters, then we have 26 letters available with us. From these 26 letters the number of different arrangements of 6 letters is:
if we are allowed to use both upper case and lower case letters, then we have 52 letters available with us. From these 52 letters the number of different arrangements of 6 letters is: