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3 years ago

Write a real world problem for 5/6 divided by 1/12

1 answer:

6 0

If you would like to divide 5/6 by 1/12, you can do this using the following steps:

5/6 / 1/12 = 5/6 * 12/1 = 10/1 = 10

The correct result would be 10.

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Suppose speeds of vehicles traveling on a highway have an unknown distribution with mean 63 and standard deviation 4 miles per h

Mashutka [201]

Answer:

The standard deviation for the sample mean distribution=0.603

Step-by-step explanation:

We are given that

Mean, $\mu=63$

Standard deviation, $\sigma=4$

n=44

We have to find the standard deviation for the sample mean distribution using Central Limit Theorem for Means.

Standard deviation for the sample mean distribution

$\sigma_x=\frac{\sigma}{\sqrt{n}}$

Using the formula

$\sigma_x=\frac{4}{\sqrt{44}}$

$\sigma_x=\frac{4}{\sqrt{2\times 2\times 11}}$

$\sigma_x=\frac{4}{2\sqrt{11}}$

$\sigma_x=\frac{2}{\sqrt{11}}$

$\sigma_x=0.603$

Hence, the standard deviation for the sample mean distribution=0.603

6 0

3 years ago

Help !! 10 points!! :)

Zolol [24]

Answer:

line f

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP 2O POINTS

vovangra [49]

C. The first is a solution, but the second is not.

5x - y/3 = 13 ; (2,-9)
substitute the letters:
5(2) - (-9/3) = 13
10 - (-3) = 13 : note that deducting a number with a negative sign turns both sign as positive.
10 + 3 = 13 ;
13 = 13

5x - y/3 = 13 ; (3,-6)
5(3) - (-6/3) = 13
15 - (-2) = 13
15 + 2 = 13
17 = 13 not equal. not a solution

hope i could help

4 0

3 years ago

Read 2 more answers

Factor completely and then place the factors in the proper location on the grid.

Alika [10]

1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).

2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.

4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.

5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)

Hope this helped :) Have a great day

8 0

4 years ago

Read 2 more answers

Bhavik bought 333 liters of milk and 555 loaves of bread for a total of \$11$11dollar sign, 11. A month later, he bought 444 lit

AnnZ [28]

Let the price of 1 litre of milk be x$

Let the price of 1 loaf of bread be y$

According to the problem

333x + 555y =11

444x+444y=10

On subtracting the two,

We get

(333x+555y=11) * 444

(444x+444y= 10) * 333

(-) (-) (-)

147852x + 246420y =4884

147852x + 147852y = 3330

(-) (-) (-)

------------------------------

98568y = 1554

y = 1554/98568

= 0.0157$

=0.02$

Price of 1 loaf of bread= 2 cents

On putting the value of y

333x + 555*0.0157 = 11333x + 8.7135 = 11333x = 2.2865x = 2.2865/333x = 0.00068$ = 0.01$

Price of 1 litre of milk = 1 cent

1.5

6 0

3 years ago