The equation that models the movement of the object is:

Where,
t: time
a: acceleration due to gravity
v0: initial speed
h0: initial height
Suppose that the object falls with zero initial velocity and from a height of 38 feet.
The equation that models the problem is:
Answer:
If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds
If by P=5ft you mean the radius is 5 then c = 2pi r or c = 10pi or approx 31.4 ft
Step-by-step explanation:
= (4)(102)
= 408 (408) (0.04) = 16.32 16.32/7.2
= 2.26666667
To solve for x we proceed as follows:
from the laws of logarithm, given that:
log_a b=c
then
a^c=b
applying the rationale to our question we shall have:
log_5 x=4
hence
5^4=x
x=625
Answer: x=625
Answer:
B 6.00
Step-by-step explanation:
M= 6$
C= 9$
M+C= 6+9= 15$ per hour