Difrence Bewteen3/4 and 1 1/2

Mathematics

1 answer:

Doss [256]2 years ago

3 0

Answer:

the difference is 3

Step-by-step explanation:

1 1/2 is equal to 6/2 so the difference would be 3

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Can someone help with this!

Sveta_85 [38]

In the given image, $a_{23}$ is 5. The correct option is the first option 5

<h3>Matrix notation</h3>

From the question, we are to determine which entry in the given matrix represents $a_{23}$

NOTE: For any entry denoted as $a_{mn}$ , it represents the entry in the <em>m</em>-th row and <em>n</em>-th column.

Thus,

$a_{23}$ represents the entry in the 2nd row and 3rd column.

In the given image, the entry in the 2nd row and 3rd column is 5.

Hence, in the given image, $a_{23}$ is 5. The correct option is the first option 5

Learn more on Matrix notation here: brainly.com/question/2382978

#SPJ1

5 0

1 year ago

Find the value of y. Round your answers to the nearest tenth

ANTONII [103]

Answer:

y ≈ 4.3

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

$\frac{AB}{RS}$ = $\frac{ED}{VU}$ , substitute values

$\frac{6}{4}$ = $\frac{8}{y+1}$ ( cross- multiply )

6(y + 1) = 32

6y + 6 = 32 ( subtract 6 from both sides )

6y = 26 ( divide both sides by 6 )

y ≈ 4.3 ( to the nearest tenth )

4 0

2 years ago

Read 2 more answers

Solve the separable differential equation dtdx=x2+164 and find the particular solution satisfying the initial condition x(0)=9

maria [59]

$\dfrac{dt}{dx} = x^2 + \frac{1}{64} \Rightarrow\ dt = \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ \\ \displaystyle \int 1 dt = \int \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ t = \dfrac{x^3}{3} + \frac{x}{64} + C$

C = 9 because all the x terms go away.

$t = \dfrac{x^3}{3} + \dfrac{x}{64} + 9$